This page accompanies the paper
"THEORY OF MIMO BIORTHOGONAL PARTNERS
AND THEIR APPLICATION IN CHANNEL EQUALIZATION"
by Bojan Vrcelj and P.P. Vaidyanathan
submitted to ICC2001
The equivalent MIMO (3-by-3) channel F(z) was taken to be:
F00(z) = - 0.2101 + 0.0067z-1 + 0.2199z-2
- 0.1177z-3 - 0.4573z-4
F01(z) = 0.0357 - 0.3351z-1 + 0.2309z-2
- 0.1434z-3
F02(z) = - 0.2653 - 3.2019z-1 - 0.4438z-2
- 0.1378z-3 + 0.0520z-4
F10(z) = 0.1863 - 3.2573z-1 - 0.3591z-2
F11(z) = 0.4892 + 0.1416z-1 - 0.1555z-2
- 0.0992z-3 - 0.1915z-4 - 0.0514z-5
F12(z) = - 0.2849 - 0.4620z-1 - 0.0211z-2
+ 0.1480z-3
F20(z) = 0.4235 - 0.2924z-1 + 0.1358z-2
F21(z) = - 0.1649 - 2.6988z-1 + 0.6550z-2
- 0.2351z-3
F22(z) = - 0.0458 + 0.3100z-1 - 0.7134z-2
+ 0.0277z-3 - 0.4219z-4
As explained in the paper, the SSE version of this channel,
F2(z) is obtained from F(z) by decimation.
According to the algorithm implicit from the simple Bezout
identity, one possible FIR FSE is given by:
H00(z) = 0.0449 - 0.0008z-2 +
0.0060z-4 - 0.0036z-6 - 0.0005z-8 - 0.0003z-10 -
0.0001z-12
H01(z) = - 0.3152 - 0.0011z-2 + 0.0002z-4
+ 0.0001z-6 - 0.0002z-8
H02(z) = - 0.0175 - 0.0756z-1 - 0.0089z-2
+ 0.0219z-3 + 0.0113z-4 + 0.0021z-5 - 0.0004z-6
+ 0.0017z-7 + 0.0007z-8 + 0.0005z-9
+ 0.0001z-10
H10(z) = - 0.0361 + 0.0242z-2 + 0.0220z-4
+ 0.0115z-6 + 0.0038z-8 - 0.0001z-10
H11(z) = 0.0193 - 0.0096z-2 -
0.0058z-4 - 0.0014z-6 - 0.0004z-8 - 0.0001z-10
H12(z) = - 0.3590 - 0.0987z-1 + 0.0079z-2
- 0.0474-3 - 0.0145z-4 - 0.0328z-5 - 0.0090z-6
- 0.0003z-7 - 0.0002z-8 - 0.0001z-10
H20(z) = - 0.3274 - 0.0840z-2 - 0.0638z-4
+ 0.0011z-6
H21(z) = 0.0635 + 0.0212z-2 + 0.0034z-4
+ 0.0021z-6
H22(z) = 0.0132 + 0.5031z-1 + 0.1467z-2 +
0.0132z-3 + 0.0010z-4 + 0.0003z-5 +
0.0028z-6 - 0.0005z-8
And finally, the third order predictor A(z) as introduced in the
Section 3 of the paper and in Fig. 3(c) is given by:
A00(z) = 1.0717 - 0.0597z-1 - 0.0080z-2 - 0.0010z-3;
A01(z) = - 0.0198 - 0.0029z-1 - 0.0001z-2;
A02(z) = 0.0198 - 0.0037z-1 - 0.0011z-2;
A10(z) = 0.8191 - 0.1412z-1 + 0.0351z-2 - 0.0001z-3;
A11(z) = 0.0047 + 0.0005z-1 + 0.0001z-2 - 0.0001z-3;
A12(z) = 0.0633 - 0.0033z-1 + 0.0012z-2 - 0.0001z-3;
A20(z) = 0.2774 - 0.0999z-1 - 0.0013z-2;
A21(z) = - 0.0217 + 0.0016z-1 + 0.0002z-2;
A22(z) = - 0.0275 - 0.0007z-1 - 0.0001z-2 + 0.0001z-3;
Go to the home pages of
Department of Electrical
Engineering,
California Institute of Technology.
Maintained by
Bojan Vrcelj
Last updated Feb, 2001